A math problem needs detailed explanation After receiving the money, the waiter remembered that the hotel was doing activities now, the original price was 10 yuan per person, and now the activity price was only 25 yuan for three people. But considering that the remaining 5 yuan was not easy for three people to share, he left 2 yuan for them, and then gave them 1 yuan each, The total price is 9 * 3 + 2 = 29 yuan, but the three of them pay 30 yuan. Where is the remaining 1 yuan?

A math problem needs detailed explanation After receiving the money, the waiter remembered that the hotel was doing activities now, the original price was 10 yuan per person, and now the activity price was only 25 yuan for three people. But considering that the remaining 5 yuan was not easy for three people to share, he left 2 yuan for them, and then gave them 1 yuan each, The total price is 9 * 3 + 2 = 29 yuan, but the three of them pay 30 yuan. Where is the remaining 1 yuan?

This problem is wrong because the author changed the concept secretly
From the payer
First of all, each of the three took out 10 yuan and returned 1 yuan. Now each of the three has 1 yuan, a total of 3 yuan
The rest of the waiter took 2 yuan
Then the owner charges 25 yuan for the stay, so 3 + 2 + 25 = 30
Starting from the payee
The shopkeeper first charged 30 minus the 5 yuan returned, which was exactly 25 yuan
In the final question, 9 yuan and 2 yuan are different concepts of money from different angles
This involves the concept of sneak exchange in logic, because the 9 * 3 = 27 (the actual hotel fee for three people) already includes the 2 yuan of the waiter and the 3 yuan returned, which is 30 yuan in total