In the parallelogram ABCD, e is the midpoint of AD, the extension line of be is at point F, connecting Ce (1), proving: CD = DF (2) if ad = 2CD, please write all right angle triangles in the graph In the parallelogram ABCD, e is the midpoint of AD, the extension line of be is at the point F, connecting Ce (1), proving: CD = DF (2) if ad = 2CD, please write all right triangles and isosceles triangles in the graph

In the parallelogram ABCD, e is the midpoint of AD, the extension line of be is at point F, connecting Ce (1), proving: CD = DF (2) if ad = 2CD, please write all right angle triangles in the graph In the parallelogram ABCD, e is the midpoint of AD, the extension line of be is at the point F, connecting Ce (1), proving: CD = DF (2) if ad = 2CD, please write all right triangles and isosceles triangles in the graph

(1) ∵ ABCD is a parallelogram, ∵ ab ∥ CD, ab = CD, ∵ EBA = f, ∵ a = EDF, ∵ e is the midpoint of CD, ∵ AE = De, ≌ Δ AEB ≌ Δ def, ≌ AB = DF, ≌ DF = CD