A 76cm long wire is surrounded into a rectangle, and the length is 5cm more than twice of the width

A 76cm long wire is surrounded into a rectangle, and the length is 5cm more than twice of the width

Let width be x, factory be 2x + 5, perimeter be (2x + 5 + x) 2 = 76
6X = 66, x = 11, length 2x + 5 = 27, 27 × 11 = 297 (square centimeter)