As shown in the figure, the total area of the whole figure is 90 square centimeters, and the area of the overlapping part of the two rectangles is equivalent to 1 / 4 of the area of the small rectangle It is equivalent to 1 / 6 of a large rectangle
Let the overlap area be x, so the large rectangle area is 6x, the small rectangle area is 4x, the total area is 6x + 4x-x = 90, x = 10, so the large rectangle area is 6x = 60 square cm, and the small rectangle area is 4x = 40 square cm