As shown in the figure, the total area of the whole figure is 90 square centimeters, and the area of the overlapping part of the two rectangles is equivalent to 1 / 4 of the area of the small rectangle It is equivalent to 1 / 6 of a large rectangle

As shown in the figure, the total area of the whole figure is 90 square centimeters, and the area of the overlapping part of the two rectangles is equivalent to 1 / 4 of the area of the small rectangle It is equivalent to 1 / 6 of a large rectangle

Let the overlap area be x, so the large rectangle area is 6x, the small rectangle area is 4x, the total area is 6x + 4x-x = 90, x = 10, so the large rectangle area is 6x = 60 square cm, and the small rectangle area is 4x = 40 square cm