AB two parallelograms are overlapped. The area of the overlapped part is one fourth of a and one sixth of B. It is known that the area of a is 12 square centimeters, so we can find the area of B
Let B be x square centimeter
12×1/4=1/6x
x=18
Let B be x square centimeter
12×1/4=1/6x
x=18