Given that the image of function f (x-1) is symmetric to the image of function g (x) with respect to the straight line y = x, and G (1) = 2, then a, f (1) = 1 B, f (2) = 1 C, f (3) = 1 D, f (0)= Given that the image of function f (x-1) is symmetric to the image of function g (x) with respect to the straight line y = x, and G (1) = 2, then a, f (1) = 1b, f (2) = 1C, f (3) = 1D, f (0) = 2

Given that the image of function f (x-1) is symmetric to the image of function g (x) with respect to the straight line y = x, and G (1) = 2, then a, f (1) = 1 B, f (2) = 1 C, f (3) = 1 D, f (0)= Given that the image of function f (x-1) is symmetric to the image of function g (x) with respect to the straight line y = x, and G (1) = 2, then a, f (1) = 1b, f (2) = 1C, f (3) = 1D, f (0) = 2

Let H (x) = f (x-1)
H (x) and G (x) are symmetric with respect to the line y = X
Then G (1) = 2
There is h (2) = 1
Because H (x) = f (x-1)
So f (x) = H (x + 1)
That is to say, move H (x) one unit to the left to get f (x)
(2,1) in H (x), one unit to the left
(1,1) in F (x)
f(1)=1
Choose a