Given that f (x) = sin ω x (ω > 0), if y = f (x), the minimum distance from a symmetry center to the symmetry axis is π / 4, try to write the analytic expression of the function

Given that f (x) = sin ω x (ω > 0), if y = f (x), the minimum distance from a symmetry center to the symmetry axis is π / 4, try to write the analytic expression of the function

f(x)=sinωx(ω>0)
Because y = f (x), the minimum distance from a symmetry center to the symmetry axis is π / 4
Then t / 4 = π / 4
That is t = π
So t = 2 π / ω = π
So omega = 2
So f (x) = sin2x
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