If the image of the function y = (1 / 2) ^ | 1-x | + m has a common point with the X axis, then the value range of M is?

If the image of the function y = (1 / 2) ^ | 1-x | + m has a common point with the X axis, then the value range of M is?

Hello. I'm glad to answer your questions. There is an intersection point with the x-axis, that is, when y = 0, you substitute y = 0 into the formula, there are: (1 / 2) ^ | 1-x | + M = 0 (1 / 2) ^ | 1-x | = - mm = - (1 / 2) ^ | 1-x | = ZM = - (1 / 2) ^ ZZ = | 1-x | ≥ - 00 > m = - (1 / 2) ^ Z ≥ - 1, so the value range of M is [- 1,0) I hope you can