Given that the image of a function of a degree passes through point a (2, - 1) and point B, where point B is the intersection point of another straight line y = negative half x + 3 on the Y axis, the function of a degree can be obtained Find the expression of this first-order function!

Given that the image of a function of a degree passes through point a (2, - 1) and point B, where point B is the intersection point of another straight line y = negative half x + 3 on the Y axis, the function of a degree can be obtained Find the expression of this first-order function!

According to the meaning of the title b (0,3)
Let the analytic formula be y = KX + B
∴ y=kx+3
Substituting x = 2, y = - 1 into y = KX + 3
The solution is k = - 2
The analytic formula is y = - 2x + 3