Calculation of anomalous integral: ∫ (1,2) 1 / [x (LNX) ^ 2] DX= Where 1 is the lower limit and 2 is the upper limit,

Calculation of anomalous integral: ∫ (1,2) 1 / [x (LNX) ^ 2] DX= Where 1 is the lower limit and 2 is the upper limit,

∫(1,2)1/[x(lnx)^2]dx
=∫(1,2)1/(lnx)^2]dlnx
=-1/lnx (1,2)
LIM (x tends to 1) (- 1 / LNX) tends to infinity
So the integral diverges