If the image of the first-order function y = KX + B (K ≠ 0) and the function y = 12x + 1 is symmetric about the x-axis and the intersection point is on the x-axis, then the expression of the function is as follows:___ .

If the image of the first-order function y = KX + B (K ≠ 0) and the function y = 12x + 1 is symmetric about the x-axis and the intersection point is on the x-axis, then the expression of the function is as follows:___ .

∵ two function images intersect on the x-axis, ∵ 0 = 12x + 1, the solution is: x = - 2, ∵ 0 = - 2K + B, ∵ y = KX + B and y = 12x + 1 about X-axis symmetry, ∵ B = - 1, ∵ k = - 12 ∵ y = - 12x-1. So the answer is: y = - 12x-1