If you make any point P in the image with inverse scale function y = 5 / x, and make a vertical line from the point to the x-axis, the perpendicular foot is Q, and the origin is O, what is the area of the triangle poq

If you make any point P in the image with inverse scale function y = 5 / x, and make a vertical line from the point to the x-axis, the perpendicular foot is Q, and the origin is O, what is the area of the triangle poq

Let the abscissa of any point of y = 5 / X be x = a,
It is easy to know that the ordinate is y = 5 / A
Therefore, the area of triangle ABC is:
(1/2)*/OQ/*/PQ/
=(1/2)*a*(5/a)
=5/2