As shown in the figure, it is known that the image of the inverse scale function Y1 = K1 / X (K1 > 0) and the linear function y2 = k2x + 1 (K2 ≠ 0) intersect at two points a and B, and AC is perpendicular to the X axis and at point C If the area of triangle OAC is 1 and AC = 2oC The analytic expressions of inverse proportion function and linear function are obtained Given that point B is (- 2, a), please observe the image and point out why the value of X is, Y1 > Y2

As shown in the figure, it is known that the image of the inverse scale function Y1 = K1 / X (K1 > 0) and the linear function y2 = k2x + 1 (K2 ≠ 0) intersect at two points a and B, and AC is perpendicular to the X axis and at point C If the area of triangle OAC is 1 and AC = 2oC The analytic expressions of inverse proportion function and linear function are obtained Given that point B is (- 2, a), please observe the image and point out why the value of X is, Y1 > Y2

Step 1: because K1 ＞ 0, the inverse proportional function is in quadrant 1 and 3. According to the analytic formula of the function, if a function passes through points (0 and 1), and the condition is AC = 2oC and OAC area is 1, then AC × OC = 2 can be obtained, and then AC = 1 and OC = 2 can be obtained. Then the coordinates of point a are (1, 2) or (- 1, - 2)