The quadratic function of higher one, the method to find the range of Y and the maximum value Y = x + √ 1-x, the value range of Y Y = x ^ 2 + √ 1-x ^ 2, find the value range of Y In y = 1 / √ ax ^ 2-ax + 1, X can take all real numbers and find the value range of A Let y = 4x ^ 2-4ax + A ^ 2-2a + 2, find the minimum value of y when x is less than or equal to 2 and greater than or equal to 0

The quadratic function of higher one, the method to find the range of Y and the maximum value Y = x + √ 1-x, the value range of Y Y = x ^ 2 + √ 1-x ^ 2, find the value range of Y In y = 1 / √ ax ^ 2-ax + 1, X can take all real numbers and find the value range of A Let y = 4x ^ 2-4ax + A ^ 2-2a + 2, find the minimum value of y when x is less than or equal to 2 and greater than or equal to 0

If it's not convenient to go straight, you can first find the inverse function (sometimes you don't need all inverse), then find its domain of definition (that is, the range of the original function), and the maximum value can be seen. But this method is useful for some functions, and it's much more convenient to learn derivative in senior three