It is known that the linear function y = (3m + 1) x + M_ 2 1 if the function image passes through the origin, 2 finds the value of M. 2 if the function image does not pass through the second quadrant, 2 finds the value of M

It is known that the linear function y = (3m + 1) x + M_ 2 1 if the function image passes through the origin, 2 finds the value of M. 2 if the function image does not pass through the second quadrant, 2 finds the value of M

1. If (0,0) is substituted, M = 2;
2. But in the second quadrant, 3M + 1 > 0 and m-2