Let y = f (x) be an odd function on the domain R, and f (X-2) = - f (x) holds for all x belonging to R, then the symmetry axis of F (x) image?

Let y = f (x) be an odd function on the domain R, and f (X-2) = - f (x) holds for all x belonging to R, then the symmetry axis of F (x) image?

f(x-2)=-f(x)=f(-x)
On x = - 1 symmetry
The odd function is symmetric about the origin, symmetric about x = - 1, and necessarily symmetric about x = 1