Given that a quadratic function has f (2 + T) = f (2-T) for any real number T, how to prove that its axis of symmetry is x = 2 Given the function f (x) = X2 (the square of x) + BX + C, for any real number T, f (2 + T) = f (2-T), how to prove that the symmetry axis of this quadratic function is x = 2?

Given that a quadratic function has f (2 + T) = f (2-T) for any real number T, how to prove that its axis of symmetry is x = 2 Given the function f (x) = X2 (the square of x) + BX + C, for any real number T, f (2 + T) = f (2-T), how to prove that the symmetry axis of this quadratic function is x = 2?

Let 2 + T = x, that is, t = X-2
f(x)=f(2-x+2)
f(x)=f(4-x)
So f (x) is a quadratic function with x = 2 as the symmetry axis
Can you see it? I don't know

Elden Ring Premiere

RELATED INFORMATIONS