If a straight line passes through the point P (- 5, - 4) and the area of the triangle enclosed by the two coordinate axes is 5, the equation of the straight line is obtained

If a straight line passes through the point P (- 5, - 4) and the area of the triangle enclosed by the two coordinate axes is 5, the equation of the straight line is obtained

Let the linear equation be XA & nbsp; + Yb = 1, then − 5A + − 4B = 112 | ab | = 5, the solution is a = 5B = − 2 & nbsp; or a = − 52b = 4. The linear equation is 2x-5y-10 = 0 or 8x-5y + 20 = 0