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Solve the equation LNX = e + 1-x
Solve the equation LNX = e + 1-x
Let f (x) = LNX + x-1-e, (x > 0),
f'(x)=1/x+1>0,
So f (x) increases monotonically, and f (E) = 0,
So the original equation has a unique solution, the solution is e
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