Use 11 squares with a perimeter of 8 decimeters to form a rectangle. What is the perimeter and area of the rectangle?

Use 11 squares with a perimeter of 8 decimeters to form a rectangle. What is the perimeter and area of the rectangle?

Because the perimeter of the small square is 8 decimeters, the side length of the small square is 2 decimeters
Therefore, the rectangle is 11 * 2 = 22 decimeters long and 2 decimeters wide
Perimeter C = 2 (length + width) = 2 (22 + 2) = 48 (decimeter)
Area s = length * width = 22 * 2 = 44 (square decimeter)