Given 10 + 3 = x + y, where x is a positive integer and 0 < y < 1, find the opposite number of X-Y

Given 10 + 3 = x + y, where x is a positive integer and 0 < y < 1, find the opposite number of X-Y

10 + 3 = x + y, where x is a positive integer and 0 < y < 1, x = 6, y = 10 + 3-6 = 10-3, X-Y = 6 - (10-3) = 9-10, and the opposite number s of X-Y is Y-X = 10-9