Known LG2 = a, Lg3 = B, try a, B for the following logarithm (fast! Thank you! lg(6) log3(4) log2(12) lg(3/2) It's true in brackets

Known LG2 = a, Lg3 = B, try a, B for the following logarithm (fast! Thank you! lg(6) log3(4) log2(12) lg(3/2) It's true in brackets

lg(6)=lg(2*3)=lg2+lg3=a+b
log3(4)=lg4/lg3=2lg2/lg3=2a/b
log2(12)=lg12/lg2=lg(4*3)/lg2=(2lg2+lg3)/lg2=(2a+b)/a
lg(3/2)=lg3-lg2=b-a