X = - 1 power of (logarithm of 1 / 2 as the base 1 / 3) + - 1 power of (logarithm of 1 / 5 as the base 1 / 3), then x belongs to the interval? A.(-2,-1) B.(1,2) C.(-3,-2) D(2,3)

X = - 1 power of (logarithm of 1 / 2 as the base 1 / 3) + - 1 power of (logarithm of 1 / 5 as the base 1 / 3), then x belongs to the interval? A.(-2,-1) B.(1,2) C.(-3,-2) D(2,3)

X = - 1 power of (logarithm of base 1 / 3 with 1 / 2) + - 1 power of (logarithm of base 1 / 3 with 1 / 5)
=Logarithm with 1 / 3 as bottom 1 / 2 + logarithm with 1 / 3 as bottom 1 / 5
=Logarithm of 1 / 10 with 1 / 3 as the base
=Logarithm of base 10 with 3
So, 2 = logarithm of 9 with 3 as the base