First simplify, then evaluate: (sin a-cos a) / (sin a + cos a), where Tan a = 2 I just don't know how to simplify. I'm preparing

First simplify, then evaluate: (sin a-cos a) / (sin a + cos a), where Tan a = 2 I just don't know how to simplify. I'm preparing

(sin a-cos a)÷(sin a+cos a)
=(tanα-1)/(tanα+1)
When Tan α = 2,
Original formula = (2-1) / (2 + 1)
=1/3