If f (x) = x ^ 3 + ax ^ 2 + BX + 27 has a maximum at x = 1 and a minimum at x = 3, then a-b=

If f (x) = x ^ 3 + ax ^ 2 + BX + 27 has a maximum at x = 1 and a minimum at x = 3, then a-b=

f(x) = x^3+ax^2+bx+27
f'(x) = 3x^2+2ax+b
f'(1) = 3 + 2a + b = 0
f'(3) = 27 + 6a + b = 0
So a = - 6, B = 9
a-b=-6-9=-15