Given x ^ 2 + XY + y ^ 2 = 1, find the maximum and minimum of u = x ^ 2 + y ^ 2 ^The second power of X, for example

Given x ^ 2 + XY + y ^ 2 = 1, find the maximum and minimum of u = x ^ 2 + y ^ 2 ^The second power of X, for example

Because x ^ 2 + y ^ 2 > = 2XY, so 1 = x ^ 2 + XY + y ^ 2 > = 3xy, that is, xy = 1 - 1 / 3 = 2 / 3, when x = y, take the equal sign, then 3 * x ^ 2 = 1, so the minimum value of x = y = 1 / radical 3 or - 1 / radical 3U is 2 / 3, because x ^ 2 + y ^ 2 + xy = 1, so (x + y) ^ 2 = 1 + XY > = 0, that is, XY > =