If sin square x-cos square x is larger than cosx SiNx, and X belongs to (0,2), then the value range of angle X is

If sin square x-cos square x is larger than cosx SiNx, and X belongs to (0,2), then the value range of angle X is

SiNx + cosx (SiNx cosx) + (SiNx cosx) > 0 (SiNx cosx) (SiNx + cosx + 1) > 0 (SiNx cosx) [2 (√ 2 / 2sinx + √ 2 / 2cosx) + 1] > 0 (SiNx cosx > 0 and sin (x + π / 4) > - √ 2