The circumference of a rectangle is 48 decimeters. If its length and width are increased by 8 decimeters, its area will increase?

The circumference of a rectangle is 48 decimeters. If its length and width are increased by 8 decimeters, its area will increase?

Let length be x and width be 24-x
Original area X (24-x) = 24x-x ^ 2
Increased area (x + 8) (24 + 8-x) = (x + 8) (32-x) = 256 + 24x-x ^ 2
So 256 + 24x-x ^ 2 - (24x-x ^ 2) = 256 square decimeters
A: an increase of 256 square decimeters

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