x. Y and Z are all positive numbers, and XYZ = 1. Prove that: (1 + X + y) (1 + y + Z) (1 + Z + Z) ≥ 27 Sorry, the letter is wrong, please verify: (1 + X + y) (1 + y + Z) (1 + Z + x) ≥ 27.

x. Y and Z are all positive numbers, and XYZ = 1. Prove that: (1 + X + y) (1 + y + Z) (1 + Z + Z) ≥ 27 Sorry, the letter is wrong, please verify: (1 + X + y) (1 + y + Z) (1 + Z + x) ≥ 27.

It is proved that by using the formula A & sup3; + B & sup3; + C & sup3; ≥ 3ABC
Then 1 + X + y ≥ 3 (XY) ^ 1 / 3
1+x+z≥3(xz)^1/3
1+z+y≥3(zy)^1/3
（1+x+y）（1+y+z）（1+z+x)≥27(x²y²z²)^1/3=27
The result of the examination is satisfactory;

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