Three inequalities are known: (1) AB > 0; (2) C / a > - D / B; (3) BC > ad If two of them are taken as conditions and the remaining one as a conclusion, a correct proposition can be formed Wrong number~ Three inequalities are known: (1) AB > 0; (2) C / AAD

Three inequalities are known: (1) AB > 0; (2) C / a > - D / B; (3) BC > ad If two of them are taken as conditions and the remaining one as a conclusion, a correct proposition can be formed Wrong number~ Three inequalities are known: (1) AB > 0; (2) C / AAD

I think your question is wrong. I should change "- C / a > - D / b" to "C / a > D / b". If it is revised, I can answer it. Because C / a > D / B, so [(CA AD) / AB] > 0, and because AB > 0, so CB ad > 0, so CB > ad. that is, serial number 1 and 2 can be derived from serial number 3. Similarly, serial number 2 can be derived from serial number 1 and 3. Similarly, serial number 1 can be derived from serial number 2 and 3