log2^x >= log4^(3x+4) How can log2 and log4 become the same base? Ah, it should be very simple for you. I hope some good people can help me, The base numbers are two and four

log2^x >= log4^(3x+4) How can log2 and log4 become the same base? Ah, it should be very simple for you. I hope some good people can help me, The base numbers are two and four

I'm right. See clearly
log2^x>= log4^(3x+4) ==> log2^x>= log2^(3x+4)/log2^4 ==>
2log2^x>=log2^(3x+4) ==> log2^(x^2)>=log2^(3x+4) ==>
x^2>=3x+4