An elementary one column inequality system to solve application problems Both a and B run on the arc Road at the same speed. If they start from the same place at the same time and walk in opposite directions, they meet every two minutes. If they walk in the same direction, they meet every six minutes. It is known that a runs faster than B, how many laps do a and B run in each minute?

An elementary one column inequality system to solve application problems Both a and B run on the arc Road at the same speed. If they start from the same place at the same time and walk in opposite directions, they meet every two minutes. If they walk in the same direction, they meet every six minutes. It is known that a runs faster than B, how many laps do a and B run in each minute?

Let a's speed be x and B's speed be y. The distance of a lap is 1
Then 2x + 2Y = 1
6X-6y=1
Solution
X=1/3
Y=1/6
So a runs 1 / 3 laps per minute, B runs 1 / 6 laps per minute
In case of this kind of problem, set the unknown quantity boldly, and then find the equation according to the known conditions. Solve the equations, and don't forget to draw a picture at the same time