For the equation of X, the square of X + 2 (K + 1) x + k = 0, the sum of two real numbers is m, and for the inequality system of Y > - 4, y < m, there is a real number solution, then the value range of K is

For the equation of X, the square of X + 2 (K + 1) x + k = 0, the sum of two real numbers is m, and for the inequality system of Y > - 4, y < m, there is a real number solution, then the value range of K is

Is the sum of two real roots m?
x²+2(k+1)x+k²=0
m=-2(k+1)
∵ Y > - 4, y < m, with real solution
∴m>-4
-2(k+1)>-4
k0
k>-1/2
∴-1/2