Y & # 178; + 4Y + 8 = y & # 178; + 4Y + 4 + 4 = (y + 2) & # 178; + 4 ≥ 4, so the minimum value of Y & # 178; + 4Y + 8 is the minimum value of M & # 178; + m + 4

Y & # 178; + 4Y + 8 = y & # 178; + 4Y + 4 + 4 = (y + 2) & # 178; + 4 ≥ 4, so the minimum value of Y & # 178; + 4Y + 8 is the minimum value of M & # 178; + m + 4

Using the method of matching
∵m²+m+4
=m²+m+1/4+15/4
=(m+1/2)²+15/4≥15/4
The minimum value of M + 4 is 15 / 4