Given that FX = √ 3-ax / A-1 (a ≠ 1), if FX is a decreasing function in the interval (0,1), then the value range of real number a is? Given FX = √ 3-ax / A-1 (a ≠ 1), if FX is a decreasing function in the interval (0,1), then the value range of real number a

Given that FX = √ 3-ax / A-1 (a ≠ 1), if FX is a decreasing function in the interval (0,1), then the value range of real number a is? Given FX = √ 3-ax / A-1 (a ≠ 1), if FX is a decreasing function in the interval (0,1), then the value range of real number a

f'(x)=-a/a-1
In this paper, we focus on the monotonicity of F '(x), (- infinity, 0) is decreasing, (0,1) is increasing, (1, + infinity) is decreasing
F '(x)