If the absolute value of the square root of (x-2y-3) + (x + 2y-5) is 0, then the square root of x square of Y is ()

If the absolute value of the square root of (x-2y-3) + (x + 2y-5) is 0, then the square root of x square of Y is ()

Because the root sign (x-2y-3) ≥ 0, | x + 2y-5 | ≥ 0
So in order to make the sum of them equal to 0, both numbers must be equal to 0, so there is
x-2y-3=0
x+2y-5=0
Simplify to
x-2y=3
x+2y=5
Add to get
2X = 8, x = 4, replace the value of X to get y = 1 / 2
X power of y = (1 / 2) 4 power = 1 / 16
The square root of 1 / 16 is ± 1 / 4
That is, the square root of the x power of Y is (plus or minus 1 / 4)