What is the range of y = x & # 178; – 4x + 3, X ∈ [0,3]?
y=(x-2)^2-1
So, x = 2 is the minimum
The minimum is - 1
When the maximum value is x = 0
The maximum value is 3
So the range is: [- 1,3]
y=(x-2)^2-1
So, x = 2 is the minimum
The minimum is - 1
When the maximum value is x = 0
The maximum value is 3
So the range is: [- 1,3]