If 2m + 6 and N-10 are the square roots of a real number and 4m + n = 7, find the value of M and n

If 2m + 6 and N-10 are the square roots of a real number and 4m + n = 7, find the value of M and n

2m + 6 and N-10 are the square roots of a real number
So: 2m + 6 = - (N-10)
2m+6=-n+10
2m+n=4
And because: 4m + n = 7
So: M = 3 / 2, n = 1