Given that a, B, C are prime numbers and a + B + C = 86, ab = BC = AC = 971, find a, B, C I found that I had the wrong number. It should be ab + BC + AC = 971... I was wrong =. =

Given that a, B, C are prime numbers and a + B + C = 86, ab = BC = AC = 971, find a, B, C I found that I had the wrong number. It should be ab + BC + AC = 971... I was wrong =. =

It is easy to know that all prime numbers except 2 are odd. According to a + B + C = 86, there is only one even prime number 2, and there must be two odd primes. Because a, B and C are symmetric, we might as well set C = 2, and substitute it into the question: a + B = 84ab + BC + AC = AB + 2 (a + b) = 971, then AB = 971 - 2 × 84 = 8