If PAB / PA = 1 / 2, PC / PD = 1 / 3, then the value of FBC / AD is? This is the answer to the 14 questions filled in the blanks in 2010 The right process Wrong number There's no F

If PAB / PA = 1 / 2, PC / PD = 1 / 3, then the value of FBC / AD is? This is the answer to the 14 questions filled in the blanks in 2010 The right process Wrong number There's no F

It seems to be a problem of sending points. The cutting line theorem obtains Pb × PA = PC × PD
∵PB=PA/2,PC=PD/3
∵∠A=∠PCB,∠D=∠PBC
∴△PBC∽△PDA
Ψ Pb / PD = BC / AD, that is BC / ad = PA / (2PD)
∵ Pb = PA / 2, PC = Pd / 3, the cutting line theorem obtains Pb × PA = PC × PD
Ψ PA & # 178 / 2 = PD & # 178 / 3, i.e. PA & # 178 / PD & # 178; = 2 / 3, i.e. PA / PD = √ 6 / 3
∴BC/AD=√6/6