Let B be an invertible matrix, a be a square matrix of the same order as B, and satisfy A2 + AB + B2 = 0. It is proved that a and a + B are invertible matrices

Let B be an invertible matrix, a be a square matrix of the same order as B, and satisfy A2 + AB + B2 = 0. It is proved that a and a + B are invertible matrices

Therefore: | - B2 | = (- 1) n | B | - 2 ≠ 0, | - A (a + b) | = | - B2 | - 0, | - A, a + B are all reversible

Elden Ring Premiere

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