Reading material, mathematician Gauss once studied such a problem in school, 1 + 2 + 3 + +10=? After research, the general conclusion of this problem is 1 + 2 + 3 + +N = n (n + 1), where n is a positive integer. Now let's study a similar problem: 1 × 2 + 2 × 3 + + n（n+1）=? Look at three special equations: 1×2=（1×2×3-0×1×2） 2×3=（2×3×4-1×2×3） 3×4=（3×4×5-2×3×4）. After reading this passage, please calculate: （1）1×2+2×3+… +100 × 101; (just write the result) （2）1×2+2×3+… +N (n + 1); (write the calculation process)

Reading material, mathematician Gauss once studied such a problem in school, 1 + 2 + 3 + +10=? After research, the general conclusion of this problem is 1 + 2 + 3 + +N = n (n + 1), where n is a positive integer. Now let's study a similar problem: 1 × 2 + 2 × 3 + + n（n+1）=? Look at three special equations: 1×2=（1×2×3-0×1×2） 2×3=（2×3×4-1×2×3） 3×4=（3×4×5-2×3×4）. After reading this passage, please calculate: （1）1×2+2×3+… +100 × 101; (just write the result) （2）1×2+2×3+… +N (n + 1); (write the calculation process)

(1)343400
(2)
1×2=（1×2×3-0×1×2）/3
2×3=（2×3×4-1×2×3）/3
3×4=（3×4×5-2×3×4）/3
.
n(n+1)=(n(n+1)(n+2)-(n-1)n(n+1))/3
So 1 × 2 + 2 × 3 + + n(n+1)=n(n+1)(n+2)/3