In five continuous natural numbers, there must be a multiple of five, In 0.1.2.3.4, if 0 is a multiple of 5, the smallest multiple of a number is itself?

In five continuous natural numbers, there must be a multiple of five, In 0.1.2.3.4, if 0 is a multiple of 5, the smallest multiple of a number is itself?

In five continuous natural numbers, there must be a multiple of five that is wrong. Although 0 is a natural number, it is not a multiple or divisor of a number. Therefore, the smallest multiple of a number is itself