Three points a (2,4) and B (0, negative 3) C and (5,1), find the cosine value of the angle between the vector AB and AC

Three points a (2,4) and B (0, negative 3) C and (5,1), find the cosine value of the angle between the vector AB and AC

Solution vector AB = (- 2, - 7), AC = (3, - 3)
That is cos = AB * AC / / AB / / AC / = (- 2 * 3 + (- 7) (- 3)) / √ (- 2) & # 178; + (- 7) & # 178; √ (3) & # 178; + (- 3) & # 178;
=15/√53*3√2
=5/√106
=5√106/106