Given that the circle x2 + Y2 + 2x-4y + 1 = 0 is symmetric with respect to the line 2aX by + 2 = 0 (a > 0, b > 0), then the minimum value of 4A + 1b is () A. 4B. 6C. 8D. 9

Given that the circle x2 + Y2 + 2x-4y + 1 = 0 is symmetric with respect to the line 2aX by + 2 = 0 (a > 0, b > 0), then the minimum value of 4A + 1b is () A. 4B. 6C. 8D. 9

From the symmetry of the circle, we can get that the line 2ax-by + 2 = 0 must pass the center of the circle (- 1, 2), so a + B = 1. So 4A + 1b = 4 (a + b) a + A + BB = 4BA + AB + 5 ≥ 24ba × AB + 5 = 9, if and only if 4BA = AB, that is, a = 2B, we take the equal sign, so we choose D