Let's relax and play a number game a2013= The first step is to take a natural number N1 = 4 and calculate the square of N1 plus one = A1 The second part calculates the sum of the numbers of A1 to get N2, and calculates the square of N2 plus one to get A2 The third step is to calculate the sum of the numbers of A2 to get N3, and calculate the square of N3 plus one to get A3 . By analogy, a2013 =?

Let's relax and play a number game a2013= The first step is to take a natural number N1 = 4 and calculate the square of N1 plus one = A1 The second part calculates the sum of the numbers of A1 to get N2, and calculates the square of N2 plus one to get A2 The third step is to calculate the sum of the numbers of A2 to get N3, and calculate the square of N3 plus one to get A3 . By analogy, a2013 =?

More calculations will reveal the law
A1 = 17, A2 = 65, A3 = 122, A4 = 26, A5 = 65, A6 = 122, a7 = 26, a8 = 65, it is found that there are three cycles after A1 and A2
2013-2 = 2011, 2011 divided by 3 = 670, so a2013 = A3 = 122 is equal to the first term in the three cycles