When m is the value, the quadratic equation MX2 + (m-1) x + M = 0 (1) If the solution set of the inequality MX2 + (m-1) x + m > 0 is r, the value range of M is obtained I think there is something wrong with the title.

When m is the value, the quadratic equation MX2 + (m-1) x + M = 0 (1) If the solution set of the inequality MX2 + (m-1) x + m > 0 is r, the value range of M is obtained I think there is something wrong with the title.

A = b-4ac
=(m-1) - 4m
=M-2m + 2-4m
=-3m-2m + 2
1. Δ is greater than 0
-3m-2m + 2 greater than 0