In △ ABC, the points o and E are on AB and AC respectively, ∠ DCB = ∠ EBC = 1,2 ∠ a, be and CD intersect at point O to prove BD = CE The following first answer is not for junior high school students, the second answer is wrong, also can't be used, hope someone continue to give guidance.

In △ ABC, the points o and E are on AB and AC respectively, ∠ DCB = ∠ EBC = 1,2 ∠ a, be and CD intersect at point O to prove BD = CE The following first answer is not for junior high school students, the second answer is wrong, also can't be used, hope someone continue to give guidance.

Firstly, a, D, O, e, and Bo = OC are obtained from ∠ DCB = ∠ EBC = 1 / 2 ∠ a;
From the sine theorem, BD / sin ∠ BOD = Bo / sin ∠ BDO = OC / sin ∠ OEC = EC / sin ∠ EOC
BD=CE

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