Given that a, B, C > 0 and 1 / (1 + a) + 1 / (1 + b) + 1 / (1 + C) = 1, we prove that ABC ≥ 8

Given that a, B, C > 0 and 1 / (1 + a) + 1 / (1 + b) + 1 / (1 + C) = 1, we prove that ABC ≥ 8

Because a > 0, b > 0, C > 0
1+a>1,1+b>1,1+c>1
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