If a, B, C > 0. ABC = 8

If a, B, C > 0. ABC = 8

Firstly, the left half is proved
1/√(1+a)+1/√(1+b)+1/√(1+c)>1/√(1+8)+1/√(1+8)+1/√(1+8)=1
To prove the right part again, we should use the method of expansion and contraction
1/√(1+a)+1/√(1+b)+1/√(1+c)
When two of them are close to zero and the other is infinite, there is a maximum, which is 2
So the whole formula